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8.3 KiB

Arguments

In Emacs lisp, keyword arguments must be passed in the same order as they were defined in, so ((lambda (a &key b c) (+ a b c)) 1 3 :b 2) will preduce an error, because b was passed as last argument but was defined as second argument.

  ((lambda (a b) (+ a b)) 1 2)         ;; 3
  ((lambda (a &key b) (+ a b)) 1 :b 2) ;; 3
  ((lambda (a &key b) (+ a b)) :b 2 1) ;; error

But if mulitiple keyword arguments are defined, their ordering does not matter.

  ((lambda (a &key b &key c &key d) (+ a b c d)) 1 :d 4 :c 3 :b 2) ;; 10

It is even possible to have a non keyword argument bewtween keyword arguments and when calling, switch the order.

  ((lambda (a &key b c &key d) (+ a b c d)) 1 :d 4  3 :b 2) ;; 10
  ((lambda (a &key b c &key d) (+ a b c d)) 1 :d 4  :b 2 3) ;; error

However somehow it is not possible to flip the ordering at the first argument

  ((lambda (a &key b) (+ a b)) 2 :b 1) ;; 3
  ((lambda (a &key b) (+ a b)) :b 2 1) ;; error
  ((lambda (&key a b) (+ a b)) :a 2 1) ;; 3
  ((lambda (&key a b) (+ a b)) 1 :a 2) ;; error

So it seems, positional arguments have to be at the exact position they were defined in, but keyword arguments can appear in any order, but at the places where keyword arguments have been defined.

Idea

Every argument can be set using keys, but keyword arguments always come strictly after positional arguments

  ((lambda (a b c d)) 1 2 3 4)             ;; ok
  ((lambda (a b c d)) 1 2 :c 2 :d 1)       ;; ok
  ((lambda (a b c d)) 1 2 :d 1 :c 2)       ;; ok
  ((lambda (a b c d)) :d 1 1 2 :c 2)       ;; error, keyword arguments must come last
  ((lambda (a b c d)) 1 2 :c 2 :d 1 :a 2)  ;; error, 'a' was passed two times

  ((lambda (a b c d)) 1 2 :d 1)             ;; error, c was not passed, but does not have a default value
  ((lambda (a b c :default 10 d)) 1 2 :d 1) ;; okay again

The drawback then is that you can never pass a keyword as a positional argument, because it will always try to assign the next argument to the variable defined by the keyword. You could still pass it as a keyword argument though. This is especially annoying because we want to use keywords as type identifiers.

(= (type "hello") :string)
  ((lambda (i-wanna-get-a-kw)) :hey)                   ;; error, unmatched value for keyword argument
  ((lambda (i-wanna-get-a-kw)) :i-wanna-get-a-kw :hey) ;; this would work again

Other Idea is to mark the place in the parameter list where keyword argumetns start and arguments before that are positional and will not be stuffed into key-value pairs and arguments after that will be keyword arguments

<lambda list> -> <positional argument>*
                 [:keys ( <keyword arguments> [:defaults-to <value>])*]
                 [(:rest <rest argument>)|(:body <body argument>)]
  (= (type "hello") :string) ;; this will work again because (=) does
                             ;; not use keyword arguments
  ((lambda (i-wanna-get-a-kw)) :hey) ;; would work because of the same reason

  (define fun
    (lambda (:keys a b c d)
      (+ a b c d)))

  (fun 1 2 3 4)             ;; okay
  (fun 1 2 :d 3 :c 4)       ;; okay
  (fun 1 2 :d 3 :c 4 :a 2)  ;; error, 'a' was passed two times
  (fun :c 1 :b 2 :d 3 :a 4) ;; okay
  (fun :c 1 :b 2 :d 3 4)    ;; error, positional argument after keyword
                            ;; and fun does not accept rest parameter

  (define fun2
    (lambda (:quoted op a b :keys c d :rest r)
      (print r)
      (op a b c d)))

>> (fun2 * 1 2 :c 3 :d 4 "this" "can" :be "whatever")
("this" "can" :be "whatever")
24


>> (define print-before-eval (lambda (:body expr)
     (print expr)
     (eval expr)))
>> (define r (print-before-eval (+ 1 2 3)))
(+ 1 2 3)
>> r
6

Wait this does not work either because you won't be able to pass keywords into rest.

Unrealated Idea: Distinguish between functions and macros

The difference is really simple:

Function

like a lambda, but no argument is automatically quoted

Macro

like a lambda, but every argument is automatically quoted

This is important, because a macro should not introduce a new environment, but use the one it lives in.


>> (define print-before-eval (macro (:rest expr)
     (print expr)
     (eval expr))

the actual problem

We have some requirements to the arguments:

  • positional arguments (always required, no default value)

  • keyword arguments (always come after positionals), can be not passed if there is a default value

  • We want to be able to have a rest paramter, where everything is dumped in to that exceeds the other parameters

The problem is, we have no way of knowing if the current keyword we are reading is still part of the keyword block or part of the rest paramter.

Consider:

  >> (define fun (lambda (a b :key c d :defaults-to 4 :rest) nil))
  >> (fun 1 2 :c 3 :d 5)


  (defun haha (par1 par2)
    (+ 1 2))

What should this be evaluated to?

a b c d rest
v1 1 2 3 5 nil
v2 1 2 3 4 (:d 5)

It is ambiguous. It is however important to note that this can only happen when there are optinal keyword arguments (keyword arguments with default values). Otherwise we could always know which variables are set and wich have not been set to see if we are in an errornious state.

Solution

We can resolve that problem by always making the the decision of chosing v1 between v1 and v1. This means, when we are expecting to read kwargs, and we encounter an kwarg, try to apply it (this can fail, for two reasons:

  1. The keyword has no following value

  2. The keyword is not a keyword argument in the funciton

), if it fails treat it as part of the rest arguments, and read all the following arguments into the rest arguments, or if it works, use it as the keyword argument.

Implementation

  typedef struct {
      char*  docstring;
      char** positional_arguments;
      struct {
          char* identifier;
          Ast_node* default_value;    // will be nullptr if no defalut value was declared
      }* keyword_arguments;
      char*  rest_argument;           // will be nullptr if no rest argument is declared
      Ast_Node_array_list body;
  } lambda;

TODO assert_equal_type macro in testing

DONE use an enum for builtin identifiers

CLOSED: [2018-10-11 Do 17:15]

TODO dont create new nils or builtins, but store one of each globally

TODO source code locations for errors

Build-in forms

DONE +

CLOSED: [2018-09-18 Di 12:14]

DONE -

CLOSED: [2018-09-18 Di 12:14]

DONE *

CLOSED: [2018-09-18 Di 12:14]

DONE /

CLOSED: [2018-09-18 Di 12:14]

TODO >

TODO <

TODO =

DONE if

CLOSED: [2018-09-18 Di 12:14]

DONE and (short circuiting)

CLOSED: [2018-10-05 Fr 22:21]

DONE or

CLOSED: [2018-10-05 Fr 22:21]

DONE not

CLOSED: [2018-10-05 Fr 22:21]

(not 1)                  ;; == (not . (1 . nil))
(not (expression 1 3))   ;; == (not . ((expression . (1 . (3 . nil))) . nil) . nil)
(not)                    ;; == (not . nil)
(not 1 2)                ;; == (not . (1 . (2 . nil)))
t

DONE first (car)

CLOSED: [2018-10-08 Mo 20:28]

DONE rest (cdr)

CLOSED: [2018-10-08 Mo 20:28]

DONE pair (cons)

CLOSED: [2018-10-08 Mo 20:28]

TODO load (import)

DONE define

CLOSED: [2018-10-08 Mo 20:28]

TODO lambda

TODO progn

DONE eval

CLOSED: [2018-10-08 Mo 20:28]

(setq condition (quote (= a 10))) (setq a 10) (eval condition) (setq a 11) (eval condition)

DONE quote

CLOSED: [2018-10-08 Mo 20:28]

DONE list

CLOSED: [2018-10-08 Mo 21:06]

  (quote (cons 2 (cons 3 (cons 4 ()))))
  ;; (cons 2 (cons 3 (cons 4 nil)))
  (quote (2 . (3 . (4 . ()))))
  ;; (2 3 4)
  (list (cons 2 (cons 3 (cons 4 ()))))
  ;; ((2 3 4))
  (list (quote(2 . (3 . (4 . ())))))

DONE print

CLOSED: [2018-10-08 Mo 20:28]

DONE read

CLOSED: [2018-10-08 Mo 20:28]

DONE type

CLOSED: [2018-10-08 Mo 21:30]

TODO info

Types

  • Symbol

  • Number

  • String

  • pair (cons-cell)

  • lambda function lambda

  • built-in function